[(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

1.) Three charges are placed 25 cm apart in an equilateral triangle. Q1 has a charge of -6.0 nC, q2 has a charge of 4.0 nC and q3 has a charge of 4.0 nC. what is the force on q2?

q1 is the top point, q2 is the bottom left leaving q3 on the bottom right

2. Relevant equations

F = K q1q2/r^2

3. The attempt at a solution

Fnet2 = F12 + F32

using the above equation for f12 i get: 3.45 * 10^-6

components:(3.45 * 10^-6) sin60 = 2.99 * 10^-6 North

:(3.45 * 10^-6) cos60 = 1.72*10^-6 East

F32 using the equation above = 2.3 *10^-7 West

combining the x components = 5.81 *10^-6 West

so using pythagoras: Root((5.81 * 10^-6)^2 + (2.99*10^-6)^2))

= 3.05 * 10 ^-6 C

angle= arctan((2.99*10^-6/ 5.81*10^-6))

= 79 degrees North of west

so my final answer is 3.05 mirco coulombs (79 degrees N of W)

Is this correct? I want to make sure i have a grasp on these problems before my final exam on the 18. Any help is greatly appreciated!

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# Homework Help: Equilateral triangle coulombs law problem

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