Equilibrium of a Rigid Body Under Coplanar Forces

Click For Summary
SUMMARY

The discussion focuses on the equilibrium of a rigid body under coplanar forces, specifically analyzing a truss system with two uniform rafters and a load. The rafters, each weighing 150N, support a 500N load at their apex, resulting in a calculated tension of 280N in the tie rope. Additionally, the center of mass and tension in a rotating system of masses connected by massless rods is examined, with the correct center of mass determined to be (0.5, 0.29) and the tension calculated incorrectly as 0.58 N instead of the expected 1/3 N.

PREREQUISITES
  • Understanding of static equilibrium and forces in truss systems
  • Familiarity with Free Body Diagrams (FBD)
  • Knowledge of rotational dynamics and center of mass calculations
  • Proficiency in applying Newton's laws of motion
NEXT STEPS
  • Study the principles of static equilibrium in truss structures
  • Learn how to effectively draw and analyze Free Body Diagrams (FBD)
  • Explore rotational dynamics, focusing on calculating tension in systems of connected masses
  • Review the application of Newton's laws in both linear and rotational contexts
USEFUL FOR

Students and professionals in engineering, physics, and mechanics, particularly those working with structural analysis and dynamics of rigid bodies.

Jordan_
Messages
20
Reaction score
0
I have a pretty tricky question here and I can't seem to figure it out. I just maybe need a slight hint?

A truss is made by hinging two uniform, 150N rafters. They rest on an essentially frictionless floor and are held together by a tie rope. A 500N load is held at their apex. Find the tension in the tie rope. ANS: 280N

Both rafters are 3m long and the tie rope is tied around them 0.5m from the bottoms.

I've been playing with this for quite a while now so any little hints would be appreciated. Maybe something that could put me in the right direction. Like for instance I'm having trouble knowing where to draw the FBD from. The hinge at the top? Or the bottom?

Thanks :smile:
 
Physics news on Phys.org
If both contact points of the beams are aligned (string is horizontal) then you can take moment by one of the contact points and find the normal force, then you can take moment by the apex and find the tension.
 
Okay thanks man! I used what you said and eventually figured it out. Interesting how it looks so hard but once you know how to do it - it seems almost like common sense :shy: .

I have one more though. I have done most of the work, but the answer I'm getting isn't the right one. Let's see what you think.

For the rotating object below determine the center of rotation, as well as the tension in the masless rods, if w = 1.0 rad/s.

(Picture of a triangle, each point being a ball, connected with rods to each other.

An equilateral triangle. All masses are 1.0kg.

ANS: (Rcm = 0.5, 0.29) and (T = 1/3 N)

To get the center of mass I did:

Rcm = [1(0, 0) + 1(0.5, 0.87) + 1(1, 0)]/3

Rcm = (0.5, 0.29)

Once I had that, I went for the radius from my starting point (0,0) to it's center of mass. Using the pyththeorem c^2 = 0.5^2 + 0.29^2 I got c = 0.58.

Using the formula:

Fnet = (m)(w^2)(R)
T = (1)(1^2)(0.58)
T = 0.58 N ?

Not the correct answer it seems. Where have I gone wrong?
 
Last edited:
i can't see anything you may have done wrong, anyone else see diffrently
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 4 ·
Replies
4
Views
6K
Replies
8
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 18 ·
Replies
18
Views
5K
Replies
4
Views
5K
  • · Replies 3 ·
Replies
3
Views
5K