Equivalence Principle: Photon Fall Near Earth's Surface

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SUMMARY

The discussion centers on the equivalence principle in relation to a photon traveling horizontally near the Earth's surface. A photon traveling 3 km horizontally does not 'fall' in the traditional sense; instead, it maintains its trajectory due to the effects of gravity being equivalent to free fall. The analogy of an elevator in free fall illustrates that from the perspective of an observer in the elevator, the photon appears to travel straight across, while an external observer would note the photon’s path as curved due to Earth's gravitational influence.

PREREQUISITES
  • Understanding of the equivalence principle in general relativity
  • Basic knowledge of photon behavior in gravitational fields
  • Familiarity with the concept of free fall and inertial frames
  • Knowledge of reference frames in physics
NEXT STEPS
  • Study the implications of the equivalence principle in general relativity
  • Explore the concept of gravitational lensing and its relation to photon paths
  • Learn about inertial vs. non-inertial reference frames in physics
  • Investigate experiments demonstrating the equivalence principle, such as those conducted in free-fall environments
USEFUL FOR

Physics students, educators, and anyone interested in the principles of general relativity and the behavior of light in gravitational fields will benefit from this discussion.

k3r0
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Homework Statement


A photon near the surface of the Earth travels a horizontal distance of 3 km. How far (in meters) does the photon 'fall' in this time? (Hint: think equivalence principle).

Homework Equations


N/A


The Attempt at a Solution


My understanding of the equivalence principle is that experiments carried out in a 'free fall' frame will have the same results as an experiment done floating in space (far from a large body). I'm confused because the photon near the surface of Earth is in neither of these situations -- so would the answer be that it doesn't 'fall' at all? I would expect it to travel horizontally only.

Thanks.
 
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k3r0 said:

Homework Statement


A photon near the surface of the Earth travels a horizontal distance of 3 km. How far (in meters) does the photon 'fall' in this time? (Hint: think equivalence principle).

Homework Equations


N/A


The Attempt at a Solution


My understanding of the equivalence principle is that experiments carried out in a 'free fall' frame will have the same results as an experiment done floating in space (far from a large body). I'm confused because the photon near the surface of Earth is in neither of these situations -- so would the answer be that it doesn't 'fall' at all? I would expect it to travel horizontally only.

Thanks.

The usual picture is to imagine an experiment carried out in an elevator (3km wide), where you shoot a beam of photons straight across the elevator. If you carry this out in space it will travel straight across. If you are in the same elevator at the Earth's surface in free fall, accelerating towards the center of the earth, from the view point of someone in the elevator it will also travel straight across. You are supposed to think of how it looks from the view point of someone who is not in the elevator and standing on the Earth's surface.
 
Thanks, I've got it now!
 

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