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Equivalent capaticnace, charge, voltage

  • Thread starter JSmith2009
  • Start date
1. Homework Statement
Find the equivalent capacitance of the circuit below. Also determine the charge of each capacitor and the potential difference across each capacitor.

http://img18.imageshack.us/img18/2616/physicss.jpg [Broken]


2. Homework Equations
Q=VC

Parallel Ceq = C1+C2+C3
V1=V2=V3
Q=Q1+Q2+Q3

Series Ceq = (1/Ceq)=(1/C1)+(1/C2)+(1/C3)
Q1=Q2=Q3
V=V1+V2+V3

3. The Attempt at a Solution
I sort of figured out the equivalent capacitance. Adding the 3 in parallel as well as the two in series on the right side, you get 13 across the top and (35/12) on the right side. Then adding the 8 and (35/12) in parallel, you get (131/12). How do I figure out capacitance from there?

I *should* be able to figure out charge/voltage from there and if not, will come back.

Thanks much!
 
Last edited by a moderator:

LowlyPion

Homework Helper
3,079
4
How do I figure out capacitance from there?
All I can say is don't stop there. Now all you have left is the 13 capacitor and the 131/12 capacitor in series. Clearly you know what to do.
 
Well, I wasn't sure if it was in series or not. I don't know why, but for some reason my mind kept telling me that it wasn't a series connector.

I guess I just needed some reassurance. Thanks :)
 

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