Find the equivalent capacitance of the circuit below. Also determine the charge of each capacitor and the potential difference across each capacitor.
Parallel Ceq = C1+C2+C3
Series Ceq = (1/Ceq)=(1/C1)+(1/C2)+(1/C3)
The Attempt at a Solution
I sort of figured out the equivalent capacitance. Adding the 3 in parallel as well as the two in series on the right side, you get 13 across the top and (35/12) on the right side. Then adding the 8 and (35/12) in parallel, you get (131/12). How do I figure out capacitance from there?
I *should* be able to figure out charge/voltage from there and if not, will come back.
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