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Equivalent capaticnace, charge, voltage

  1. Mar 18, 2009 #1
    1. The problem statement, all variables and given/known data
    Find the equivalent capacitance of the circuit below. Also determine the charge of each capacitor and the potential difference across each capacitor.

    http://img18.imageshack.us/img18/2616/physicss.jpg [Broken]


    2. Relevant equations
    Q=VC

    Parallel Ceq = C1+C2+C3
    V1=V2=V3
    Q=Q1+Q2+Q3

    Series Ceq = (1/Ceq)=(1/C1)+(1/C2)+(1/C3)
    Q1=Q2=Q3
    V=V1+V2+V3

    3. The attempt at a solution
    I sort of figured out the equivalent capacitance. Adding the 3 in parallel as well as the two in series on the right side, you get 13 across the top and (35/12) on the right side. Then adding the 8 and (35/12) in parallel, you get (131/12). How do I figure out capacitance from there?

    I *should* be able to figure out charge/voltage from there and if not, will come back.

    Thanks much!
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Mar 18, 2009 #2

    LowlyPion

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    Homework Helper

    All I can say is don't stop there. Now all you have left is the 13 capacitor and the 131/12 capacitor in series. Clearly you know what to do.
     
  4. Mar 18, 2009 #3
    Well, I wasn't sure if it was in series or not. I don't know why, but for some reason my mind kept telling me that it wasn't a series connector.

    I guess I just needed some reassurance. Thanks :)
     
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