Equivalent Circuit: Re-Draw OK?

princejan7 · Feb 17, 2014

Just wondering if its ok to re-draw this
http://postimg.org/image/a074v6cor/

as this
http://postimg.org/image/uvtf6f8vv/

?

BvU · Feb 17, 2014

Hello, your higness. Not your first post, so you should know better by now. Use the template and don't make me chase links instead of going to sleep. Maybe tomorrow.

But, out of curiosity: is the central point in the first picture a connection or is I1 = -I3 ?

lewando · Feb 17, 2014

Whether the central point is connected or not, the redrawing is not correct. One discrepancy (and there are others): in the original drawing, the 4 Ω and the 6 Ω share a node. In the redrawing, they do not.

SammyS · Feb 17, 2014

princejan7 said:

Just wondering if its ok to re-draw this
http://postimg.org/image/a074v6cor/

as this
http://postimg.org/image/uvtf6f8vv/

?

No

Circuit schematic with a 10 V source on top, 8 V source on bottom, 4 A and 1 A current sources, resistors 6 Ω, 12 Ω, 4 Ω and 2 Ω, and currents I1, I2, I3 labelled, with problem text *3.55 above.

Is not the same as

Hand-drawn circuit schematic with a 6 Ω resistor on top, a 1 A current source at top right, a 10 V source, a 4 A current source on the left, an 8 V source, and 2 Ω, 12 Ω and 4 Ω resistors.

Your circuit would force I₃ = -I₂

and I₁ = 1 Amp

willem2 · Feb 18, 2014

It would be correct if you add a wire from the point between the 4 and 12 ohm resistors at the bottom to the point between the 6 ohm resistor and the 1 amp current source at the top. You separated the 4 wires coming together in the midpoint into 2 pairs.

Equivalent Circuit: Re-Draw OK?

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