Equivalent Circuit: Re-Draw OK?

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    Circuit Equivalent
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Homework Help Overview

The discussion revolves around the validity of redrawing an equivalent circuit diagram, specifically comparing two circuit representations. The subject area pertains to circuit analysis and electrical engineering concepts.

Discussion Character

  • Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore whether the central point in the original circuit is a connection or if it implies a current relationship. There are attempts to clarify discrepancies between the original and redrawn circuits, particularly regarding node connections and current directions.

Discussion Status

The discussion is ongoing, with some participants providing guidance on the necessary connections for the redrawn circuit to be valid. Multiple interpretations of the circuit's connections are being explored, but there is no explicit consensus on the correctness of the redraw.

Contextual Notes

There are references to a template that should be followed for posting, indicating potential constraints on how information is presented. The discussion also highlights specific circuit elements and their relationships, which are under scrutiny.

princejan7
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Just wondering if its ok to re-draw this
http://postimg.org/image/a074v6cor/

as this
http://postimg.org/image/uvtf6f8vv/


?
 
Last edited by a moderator:
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Hello, your higness. Not your first post, so you should know better by now. Use the template and don't make me chase links instead of going to sleep. Maybe tomorrow.

But, out of curiosity: is the central point in the first picture a connection or is I1 = -I3 ?
 
Whether the central point is connected or not, the redrawing is not correct. One discrepancy (and there are others): in the original drawing, the 4 Ω and the 6 Ω share a node. In the redrawing, they do not.
 
princejan7 said:
Just wondering if its ok to re-draw this
http://postimg.org/image/a074v6cor/

as this
http://postimg.org/image/uvtf6f8vv/

?
No


attachment.php?attachmentid=66728&stc=1&d=1392691615.png


Is not the same as

attachment.php?attachmentid=66729&stc=1&d=1392691712.png


Your circuit would force I3 = -I2

and I1 = 1 Amp
 

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Last edited by a moderator:
It would be correct if you add a wire from the point between the 4 and 12 ohm resistors at the bottom to the point between the 6 ohm resistor and the 1 amp current source at the top. You separated the 4 wires coming together in the midpoint into 2 pairs.
 

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