Equivalent Expression for Cot 50 Degrees

[TonyC]

How do I go about finding the equivalent expression for cot 50 degrees?

When I work the problem, I come up with tan 130 degrees.

Where am I going wrong?

 

[TD]

I rather work in radians, if you don't mind.

50^\circ = \frac{{5\pi }}{{18}}

We know that:
\cot \left( \alpha \right) = \tan \left( {\frac{\pi }{2} - \alpha } \right)

So:
\cot \left( {\frac{{5\pi }}{{18}}} \right) = \tan \left( {\frac{\pi }{2} - \frac{{5\pi }}{{18}}} \right) = \tan \left( {\frac{{2\pi }}{9}} \right) = \tan \left( {40^\circ } \right)

 

[TonyC]

That makes perfect sense now...

The light has come on, thank you

 

[TD]

No problem