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Equivalent Resistance in series circuit

  1. Feb 17, 2010 #1
    1. The problem statement, all variables and given/known data
    Three resistors with values of 7.0 Omega, 12 Omega, and 16 Omega are connected in series in a circuit with a 9.0 V battery.
    a) What is the total equivalent resistance?
    b) What is the current in each resistor?
    c) At what rate is energy delivered to the 16 Omega resistor?
    2. Relevant equations

    I= V/Rs
    P = V^2 /R ???

    3. The attempt at a solution
    I got "a" but missed "b". i used the first equation and got .26 then divided that by 3 but I guess that's not what you do. For "c" i really have no clue. help!!!
     
  2. jcsd
  3. Feb 17, 2010 #2

    rl.bhat

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    In series connection the current is the same in all the resistances.
    For "c", the power can also be written as P = I^2*R.
     
  4. Feb 17, 2010 #3
    so for b the answer would be just .26 and not divide by 3?
     
  5. Feb 18, 2010 #4

    rl.bhat

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  6. Feb 18, 2010 #5
    thanks!
     
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