Find the equivalent resistance between terminals a and b
Series: Req = summation of resistors
Parallel 1/Req = summation of 1/resistances
The Attempt at a Solution
So I figured out the easy ones, and so I'm here at the moment:
And that is where I am stuck. The problem I am finding is that everything is intertwined and I can't figure out how to simplify anymore.
For example, I feel the next step is to combine the 6 ohm and the 5 ohm resistor in the middle. But I can't say they are in parallel, with the 3 ohm and the 6 ohm being in series, as the other 6 ohm resistor is there tacked on. So the 3 ohm resistor is in parallel with the two 6 ohm ones. But again, I can't use the parallel equal for those because the right 6 ohm resistor is connected to the 1 ohm resistor, and I can't say the 6 ohm and the 1 ohm are in series, because the 5 ohm and the top 1 ohm are also connected to it. And I can't say the top 1 ohm, the 3+6+6 ohm portion, and the 5 ohm portion are all in parallel, because the 1 ohm connects at the top and at the bottom.
Basically, I have no clue where to start. I've been looking up example problems on the internet all afternoon and none of them I've found have had these issues.
Thanks in advance for the help! I am sure I can figure it out if someone could push me in the right direction. I am just not sure where my understanding of the concepts is wrong.