- #1

yaro99

- 75

- 0

## Homework Statement

(I added in the R values for reference)

## Homework Equations

**GV=I**

KCL

## The Attempt at a Solution

I am not concerned with the MATLAB portion of the problem, only the setup.

I think what the problem wants me to do is:

1) connect a 1A test current from the ground source to v

_{1}(like shown in the picture), find v

_{1}using node voltage analysis, then find the equivalent resistance by dividing the test voltage (v

_{1}) by the test current, which is 1A.

2) connect a 1A test current from the ground source to v

_{2}. Repeat steps, where now v

_{2}is the test voltage, to get equivalent resistance.

3) same as above, except with v

_{4}.

When I set up my system of equations I get too many unknowns.

For example, trying KCL on case 1 (where 1A is connected to v

_{1}), I get this system of equations:

v

_{1}/R

_{1}+ (v

_{1}-v

_{2})/R

_{2}+ (v

_{1}-v

_{3})/R

_{6}= i

_{test}

(v

_{2}-v

_{1})/R

_{2}+ (v

_{2}-v

_{4})/R

_{7}+ (v

_{2}-v

_{7})/R

_{3}= 0

(v

_{4}-v

_{2})/R

_{7}+ (v

_{4}-v

_{3})/R

_{11}+ (v

_{4}-v

_{6})/R

_{12}= 0

Plugging in 1 for i and for all R values still gives me 6 different voltages to solve for, and only 3 equations.

Using the same method for case 2 and 3 (where v

_{test}is v

_{2}and v

_{4}respectively), I get nearly identical systems of equations, the only difference being which equation is set equal to i instead of 0.