Equivalent stiffness and damping

Click For Summary
SUMMARY

The discussion focuses on calculating equivalent stiffness and damping in a system of springs and dampers. The key equations presented are for stiffness in series (keq=ka*kb/(ka+kb)) and in parallel (keq=ka+kb), which also apply to dampers. The confusion arises regarding the arrangement of springs k1, k2, and k3, where the textbook asserts that k3 is in parallel with k1 and k2, leading to a total stiffness calculation of keq=k1+k2+k3. The correct interpretation of the arrangement of dampers c1 and c2 is also clarified, reinforcing the need to apply Newton's laws for accurate analysis.

PREREQUISITES
  • Understanding of mechanical systems involving springs and dampers
  • Familiarity with Newton's laws of motion
  • Knowledge of equivalent stiffness calculations in series and parallel configurations
  • Basic proficiency in algebra for manipulating equations
NEXT STEPS
  • Study the derivation and application of equivalent stiffness formulas for complex spring-damper systems
  • Learn about the dynamics of systems with multiple degrees of freedom
  • Explore the impact of damping ratios on system behavior
  • Investigate real-world applications of spring-damper systems in engineering
USEFUL FOR

Mechanical engineers, physics students, and anyone involved in the design or analysis of mechanical systems with springs and dampers will benefit from this discussion.

Hood
Messages
7
Reaction score
0

Homework Statement


A scheme of springs and dampers is given. What is equivalent stiffness and damping?

vibrations.png


Homework Equations


For stiffness in series: keq=ka*kb/(ka+kb)
For stiffness in parallel: keq=ka+kb
For dampers similarly.

The Attempt at a Solution



To me it looks like k1 and k2 are in parallel. After summation I'd say that k3 is in series and calculate for that. Dampers c1 and c2 seem to be in series so I'd calculate them similarly.

I'm puzzled because textbook says that k3 is parallel to k1 and k2 and simply sums it up (keq=k1+k2+k3). I doubt it's like that, could you also explain about c1 and c2?
 
Physics news on Phys.org
Hood said:

Homework Statement


A scheme of springs and dampers is given. What is equivalent stiffness and damping?

vibrations.png


Homework Equations


For stiffness in series: keq=ka*kb/(ka+kb)
For stiffness in parallel: keq=ka+kb
For dampers similarly.

The Attempt at a Solution



To me it looks like k1 and k2 are in parallel. After summation I'd say that k3 is in series and calculate for that. Dampers c1 and c2 seem to be in series so I'd calculate them similarly.

I'm puzzled because textbook says that k3 is parallel to k1 and k2 and simply sums it up (keq=k1+k2+k3). I doubt it's like that, could you also explain about c1 and c2?

Best thing to do is go back to Newton: mx'' = ƩFx.

Call x = 0 when the mass is in its equilibrium position. If m goes up (x > 0) what are the forces acting on m?

You will see that your textbook is right ...
 

Similar threads

Replies
2
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
2
Views
2K
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 9 ·
Replies
9
Views
3K