I have a fairly decent understanding of black holes, but have always had one curiosity that I haven't found a distinct answer to:(adsbygoogle = window.adsbygoogle || []).push({});

If light, through whatever reaction, is emitted inside the event horizon of a black hole such that it is directed in a path exactly orthogonal to the black hole, i.e., 180 degrees relative to the direction of the gravitational force, is it able to escape since the photon must travel at c?

The reason I specify its direction is because I understand that if there is even the slightest angle, the fact that the escape velocity is greater than c would cause it to spiral back into the singularity.

Obviously the photon cannot escape (or can it?), I am simply looking for the explanation. The only theory I have been able to formulate that would dictate the photon to return is that at the singularity, spacetime is distorted to such a point that any direction pointing away from the singularity loops back inward.

Any insight would be greatly appreciated, thanks in advance!

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# Escape of light perfectly orthogonal to black hole

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