Escape Velocity Calculation for an Object on Earth

[Stratosphere]

How do you Calculating the escape velocity? I googled it but they give bad instructions on how to do it. What is the formula?

 

[Stratosphere]

Every time I try using the formula i have i have to solve for V^2 and I get it to equal 35
3541. Is this right? I plug in the numbers like it says it I still don't get the right answer.

 

[mgb_phys]

Gravitational potential energy is = GMm/r (where M is the mass of the earth)
Kinetic energy = 1/2 m v^2

You start at r=radius of Earth and end up at r=infinity.
A bit of rearranging and a subtraction and it shoudl be easy

 

[Stratosphere]

I set KE=GPE i get a velocity of 465,561 for a 10kg object. This doesn't seem right.

 

[Nabeshin]

I set KE=GPE i get a velocity of 465,561 for a 10kg object. This doesn't seem right.

Well escape velocity is a function of radius so this question, as you stated, makes no sense...

 

[Janus]

Every time I try using the formula i have i have to solve for V^2 and I get it to equal 35
3541. Is this right? I plug in the numbers like it says it I still don't get the right answer.

What formula are you using?

 

[Stratosphere]

What formula are you using?

V$$^{2}$$=$$\frac{2GM}{R}$$ to find the escape velocity of the Earth and i get, 465561.808.

 

[sylas]

$V^{2}=\frac{2GM}{R}$ to find the escape velocity of the Earth and i get, 465561.808.

You've got "tex" tags inside your formula. I've tried to fix tags in the quoted extract; but it is still not displaying for some reason. But the formula looks fine to me. Just make sure all your variables are in consistent units. You give a number, but no units. Are you meaning km/hr, or m/s, or something else?

The gravitational constant G is usually given in SI units. If you do everything in meters and seconds and kilograms, it will work.

 

[Janus]

Every time I try using the formula i have i have to solve for V^2 and I get it to equal 35
3541. Is this right? I plug in the numbers like it says it I still don't get the right answer.

Okay, from this answer, I'd say that you are using kilometers instead of meters for the radius of the Earth.

 

[mgb_phys]

Why would the mass of the object matter ?

GM for the Earth is almost exactly 400,000 km^3/s^2 (worth remembering)
The radius of the Earth is around 6400km

so v^2 = 2GM/r = 2*400,000/6400 = 225km^2/s^2
v = 11.2km/s (roughly)

edit - sorry i posted this straight after you replied, but it didn't show up (got a database error message)