Calculating Escape Velocity for Earth: Where Am I Going Wrong?

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SUMMARY

The discussion centers on calculating the escape velocity for Earth using the formula vescape = Sqrt(2GM/r). The user initially miscalculated the escape velocity by incorrectly using the radius of Earth in kilometers instead of meters, leading to an erroneous result of 353,541 m/s instead of the correct 11.2 km/s. The correct approach involves substituting the radius of Earth as 6,378,000 meters, which aligns with the standard gravitational constant G = 6.67 x 10^-11 and Earth's mass M = 5.976 x 10^24 kg. The key takeaway is the importance of using consistent units in calculations.

PREREQUISITES
  • Understanding of gravitational constant (G = 6.67 x 10^-11 N(m/kg)^2)
  • Knowledge of Earth's mass (M = 5.976 x 10^24 kg)
  • Familiarity with the formula for escape velocity (vescape = Sqrt(2GM/r))
  • Ability to convert units, specifically between kilometers and meters
NEXT STEPS
  • Review the derivation of the escape velocity formula vescape = Sqrt(2GM/r)
  • Practice unit conversion between kilometers and meters for scientific calculations
  • Explore the implications of escape velocity in astrophysics and space travel
  • Learn about gravitational forces and their impact on orbital mechanics
USEFUL FOR

Students in physics, aerospace engineers, and anyone interested in understanding gravitational physics and escape velocity calculations.

breid040
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Homework Statement
Find the escape energy of earth. Earth's radius is 6378km, its mass is 5.976x10^24kg, and the universal gravitational constant is 6.67x10^-11
Relevant Equations
vescape=Sqrt(2MG/r)
I really cannot understand where this is going wrong...
Plugging in the constants, I get
vescape=Sqrt(2(6.67x10^-11)(5.976x10^24kg)/6378).

(6.67x10^-11)(5.976x10^24kg) gives me 3.99x10^14, and multiplied by 2 gives me 7.97x10^14.

7.97x10^14/6378=1.25x10^11.
The square root of 1.25x10^11 would give 353541 m/s. I know that this is not right, as the escape velocity of Earth is 11.2 km/s.

If I divide 2MR by 6378000, then it gives me the correct answer... but this is not the radius of the earth. I genuinely am stumped. I've typed this carefully into my calculator many times. Help is greatly appreciated.
 
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When substituting for r, what should be the units for r?
 
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TSny said:
When substituting for r, what should be the units for r?
Ah. Meters. Thanks so much... can't believe I missed that!
 
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