1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Estimating area with finite sums

  1. Sep 8, 2010 #1
    1. The problem statement, all variables and given/known data
    Use the midpoint rule to estimate the area under the graph of f(x) = 7/x and above the graph of f(x) = 0 from [1,25] using two rectangles of equal width.

    2. Relevant equations

    3. The attempt at a solution
    So first I found [tex]\Delta[/tex]x by using (b-a) / n and got (25 - 1) / 2 = 12.

    Then I usually proceed by drawing out a number line from 1 to 25 and dividing it up into my 2 segments, each being 12 units wide, i.e. 1---12---25.

    Here's where I get stuck. For some odd reason, this midpoint rule throws me off like crazy. I completely understand the left/right endpoint rule, and would have breezed through this problem if it were either of these. This sounds really, really stupid, but I'm not sure how to find the midpoint of each segment without making a mistake. In class we've only gone through examples where each segment is 3 units wide, so the midpoint is very obvious (i.e. 1-3, the midpoint would be 2). How do I do this accurately?

    In my mind, I'm thinking that finding the midpoint of each 2 segments would be the same as dividing 1 to 25 into 4 equal parts, so my xi values would be 6 and 18. But when I use these to calculate my area estimate, my answer doesn't match my textbook's. What am I doing wrong, and is there a quick and easy way to find a midpoint that isn't obvious? I feel like I'm over complicating things.
  2. jcsd
  3. Sep 8, 2010 #2
    Well, you found the length of each rectangle (12) but remember it is 12 from 1 not 12 from 0 (hopefully that makes sense).

    You would then have 1...13...25. Can you finish from here?
  4. Sep 8, 2010 #3
    Oh, ok. I see what you're saying about the lengths.

    So would my midpoints be 7 and 19? What I'm trying to get at is if there's a really easy mathematical way to get the midpoints of these segments. At this point I'm basically being really methodical about it, using my elementary school techniques for finding the median of a set of numbers.
  5. Sep 8, 2010 #4


    User Avatar
    Science Advisor

    Yes, those are the midpoints. Now, you approximate the "area under the curve" as the area of two rectangles, each having base 12, the first with height f(7) and the second with height f(19).
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook