# Euler's Method question.

1. Mar 24, 2006

### que

I need some clarification please the question is:
-Using Euler's method with h = .25 given dy/dx = ycosx ,y(0) = 1 on the interval 0 <= x =< pi/4.

are the X's : pi/12, pi/6, pi/4 OR .25, .50, .75 ??

que.

2. Mar 25, 2006

### Integral

Staff Emeritus
$$x_0=0$$
$$x_1 = x_0 +h$$
$$x_3 = x_0 + 2*h$$

Continue until

$$x_n > \frac { \pi } 4$$

3. Mar 25, 2006

### HallsofIvy

Staff Emeritus
Start at 0 and go by steps of h:
0, .25, .50, .75, 1, 1.25, 1.50.

It's a bit peculiar to use an h that does not divide evenly into the length of the interval. Are you sure you have read the problem correctly?

4. Mar 26, 2006

### que

ok so what i get.
(x0,y0) = (0,1)
X1 = .25
Y1 = 1 + .25(1*cos(0)) = 1.25
i do this until x3,y3 where x3 = .75, and y3 = 1.8935
do i stop there since doing one more step will be > pi/4?

thanx.

5. Mar 26, 2006

### que

yes HallsofIvy i read the problem correctly that why i was confused since all the book problems use an h that is divide evenly into the length of the intervals.