Euler's Totient Function Proving

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To prove that if m and n are positive integers such that m|n, then φ(mn) = mφ(n), one can utilize Euler's formula for the totient function. The relationship stems from the fact that the prime factorization of m shares the same factors as n due to the divisibility condition. An alternative approach involves counting the integers coprime to nm within the range of 1 to mn and demonstrating that this count matches those coprime to n within 1 to n. Both methods highlight the connection between the totient function and the structure of the integers involved. Understanding these relationships is crucial for proving the statement effectively.
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I need some help/hints on how to prove this statement. I don't know where to start!


Prove that if m and n are positive integers such that m|n, then φ(mn) = mφ(n).

Thanks
 
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It's a direct consequence of Euler's formula:
<br /> \phi\left(n\right)=n(1-\frac{1}{p_1})(1-\frac{1}{p_2}) \cdots (1-\frac{1}{p_k})<br />
Because the hypothesis implies that the prime factorization of m has the same factors as n.

Or you can count the numbers that are coprime with nm in \left\{1,\ldots,mn\right\} and prove that there are as many as the ones that are coprime with n in \left\{1,\ldots,n\right\}.
 
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