Evaluate a Definite Integral to find Work

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SUMMARY

The discussion focuses on evaluating the integral ∫(y^2 + 2xy(dy/dx))dx from x=0 to x=1 and y=0 to y=1. Participants clarify that the integral is not a double integral but rather a line integral evaluated along the line y = x. By substituting y = x and dy/dx = 1, the integral simplifies, allowing for straightforward integration with respect to x. The integrand can also be expressed as d(f(x,y)), indicating that the result is path-independent.

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  • Familiarity with substitution methods in calculus
  • Knowledge of partial derivatives and their notation
  • Basic concepts of path independence in vector calculus
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bmb2009
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Homework Statement


Evaluate: from x=0 to x=1 and y=0 to y=1

∫(y^2 + 2xy(dy/dx))dx and carry the integration out over x



Homework Equations





The Attempt at a Solution


I know how to calculate double integrals with multiple variables but the (dy/dx) throws me off and it says to carry out the integration over x which to means that it isn't a double integral at all? Can some one explain to me how to deal with this integral? Thanks!
 
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bmb2009 said:

Homework Statement


Evaluate: from x=0 to x=1 and y=0 to y=1

∫(y^2 + 2xy(dy/dx))dx and carry the integration out over x

Homework Equations





The Attempt at a Solution


I know how to calculate double integrals with multiple variables but the (dy/dx) throws me off and it says to carry out the integration over x which to means that it isn't a double integral at all? Can some one explain to me how to deal with this integral? Thanks!

The question is somewhat unclear, but I think it is asking you to evaluate the given line integral over the line y = x from (0,0) to (1,1). So substitute y = x and dy/dx = 1 in the integrand and integrate with respect to x.
 
bmb2009 said:

Homework Statement


Evaluate: from x=0 to x=1 and y=0 to y=1

∫(y^2 + 2xy(dy/dx))dx and carry the integration out over x
The integrand has a rather interesting property. It can be written in the form d(f(x,y)). So the answer will be independent of path.
 

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