MHB Evaluate Integral: Get Help Now!

  • Thread starter Thread starter Lhh
  • Start date Start date
  • Tags Tags
    Integral
Lhh
Messages
3
Reaction score
0
Can someone help me with this? Not sure where to start.

Exercise 1 (integration) Evaluate the integral

∫0.2e^−0.2u du.
10
 

Attachments

  • 54774788-341B-4B4F-BAAE-139434206B87.jpeg
    54774788-341B-4B4F-BAAE-139434206B87.jpeg
    556.1 KB · Views: 130
Last edited:
Physics news on Phys.org
$t = 0.2u \implies dt = 0.2 \, du$

substitute and reset the limits of integration

$\displaystyle \lim_{b \to \infty} \int_{2}^b e^{-t} \, dt$

$\displaystyle \lim_{b \to \infty} \bigg[-e^{-t} \bigg]_2^b$

$\displaystyle -\lim_{b \to \infty} \bigg[e^{-b} - e^{-2} \bigg] = -\bigg[0 - \dfrac{1}{e^2} \bigg] = \dfrac{1}{e^2}$
 
Back
Top