MHB Evaluate Integral: Get Help Now!
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The integral to evaluate is ∞ ∫0.2e^−0.2u du. A substitution is made with t = 0.2u, leading to dt = 0.2 du and adjusted limits of integration from 2 to b. The evaluation involves taking the limit as b approaches infinity, resulting in the expression -[-e^{-b} + e^{-2}]. As b approaches infinity, the term e^{-b} approaches zero, simplifying the result to 1/e^2. The final answer for the integral is 1/e^2.
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