MHB Evaluate Product: Limit of Product Involving Tangents

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The limit of the product involving tangents is evaluated by analyzing the expression as n approaches infinity. The term inside the product, \(1 + \tan\left(\frac{1}{n+k}\right)\), can be approximated using the small-angle approximation for tangent. As n grows large, the product converges to an exponential form, leading to the conclusion that the limit evaluates to a specific value. The suggested solution involves recognizing that the product can be transformed into a sum in the exponent. Ultimately, the limit converges to a finite value as n approaches infinity.
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Evaluate the product:

\[\lim_{n\to \infty}\prod_{k=1}^{n}\left(1+\tan \left(\frac{1}{n+k}\right)\right), \;\;\; n,k \in \Bbb{N}.\]
 
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Hint:

\[\lim_{x \rightarrow 0}\frac{\tan x}{x} = 1\]
 
Suggested solution:
Let the limit be $L$.We have:

\[\lim_{n\rightarrow \infty }\frac{\tan\left ( \frac{1}{n+k} \right )}{\frac{1}{n+k}} =\lim_{n\rightarrow \infty }(n+k)\tan\left ( \frac{1}{n+k} \right ) = 1,\;\;\; 1 \le k \le n.\]

Hence:

\[L = \lim_{n \rightarrow \infty }\prod_{k=1}^{n}\left ( 1+ \frac{1}{n+k}\right ) = \lim_{n\rightarrow \infty } \frac{2n+1}{n+1} =2.\]
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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