MHB Evaluate Product: Limit of Product Involving Tangents

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The limit of the product involving tangents is evaluated by analyzing the expression as n approaches infinity. The term inside the product, \(1 + \tan\left(\frac{1}{n+k}\right)\), can be approximated using the small-angle approximation for tangent. As n grows large, the product converges to an exponential form, leading to the conclusion that the limit evaluates to a specific value. The suggested solution involves recognizing that the product can be transformed into a sum in the exponent. Ultimately, the limit converges to a finite value as n approaches infinity.
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Evaluate the product:

\[\lim_{n\to \infty}\prod_{k=1}^{n}\left(1+\tan \left(\frac{1}{n+k}\right)\right), \;\;\; n,k \in \Bbb{N}.\]
 
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Hint:

\[\lim_{x \rightarrow 0}\frac{\tan x}{x} = 1\]
 
Suggested solution:
Let the limit be $L$.We have:

\[\lim_{n\rightarrow \infty }\frac{\tan\left ( \frac{1}{n+k} \right )}{\frac{1}{n+k}} =\lim_{n\rightarrow \infty }(n+k)\tan\left ( \frac{1}{n+k} \right ) = 1,\;\;\; 1 \le k \le n.\]

Hence:

\[L = \lim_{n \rightarrow \infty }\prod_{k=1}^{n}\left ( 1+ \frac{1}{n+k}\right ) = \lim_{n\rightarrow \infty } \frac{2n+1}{n+1} =2.\]
 

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