- #1
mathwizarddud
- 25
- 0
[tex]\int_0^\infty \; \frac{ \ln\;(1+x^2)}{ x^2+2x\;\cos\;\theta + 1 }\;\;dx[/tex]
[tex]\theta \in \mathbb{R}[/tex]
[tex]\theta \in \mathbb{R}[/tex]
HallsofIvy said:Why?
Gib Z said:Differentiation under the integral sign looks like it'll work here.
Evaluating an improper integral means finding the numerical value of the integral, which represents the area under the curve of a function that has an infinite or undefined limit.
The evaluation of an improper integral involves taking the limit of the integral as one or both of the integration bounds approach infinity. This is not necessary for a regular integral, where the integration bounds are finite.
Some common techniques for evaluating improper integrals include using the limit definition, using properties of integrals, and breaking the integral into smaller integrals.
An improper integral converges if the limit of the integral exists, and if the function being integrated approaches a finite value or approaches zero as the integration bounds approach infinity.
Yes, an improper integral can have multiple convergence points. This means that the integral can converge to different values depending on the chosen integration bounds.