Evaluate the integral after figuring out the proper method to use

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SUMMARY

The integral ∫ ((2t+3)^2)/t^2 dt can be simplified by multiplying the numerator out and then splitting the integral into simpler parts. The original poster initially attempted to use integration by parts, which was not covered in their coursework, leading to confusion. The recommended method involves expanding the numerator to facilitate straightforward integration, making the problem more manageable.

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Homework Statement


∫ ((2t+3)^2)/t^2 dt


Homework Equations





The Attempt at a Solution


I figured that I would use integration by parts. The problem I'm having is that we haven't actually learned integration by parts, only the u substitution method. I went ahead and read the book on the proof and several examples, but its still a bit new to me so I'm not sure how to approach he problem.

u=1/t^2
du=-dt/3t^3

∫dv∫=(2t+3)^2 dt
v=(4t^3)/3 +6t^2 +9t

4t/3 +6+9/t - ∫ ((4t^3)/3 +6t^2 +9t)/t^3 dt

Is there a more straight forward way of solving this?
 
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Painguy said:

Homework Statement


∫ ((2t+3)^2)/t^2 dt


Homework Equations





The Attempt at a Solution


I figured that I would use integration by parts. The problem I'm having is that we haven't actually learned integration by parts, only the u substitution method. I went ahead and read the book on the proof and several examples, but its still a bit new to me so I'm not sure how to approach he problem.

u=1/t^2
du=-dt/3t^3

∫dv∫=(2t+3)^2 dt
v=(4t^3)/3 +6t^2 +9t

4t/3 +6+9/t - ∫ ((4t^3)/3 +6t^2 +9t)/t^3 dt

Is there a more straight forward way of solving this?

Sure there is. Just multiply the numerator out. Then split it up and integrate.
 
Dick said:
Sure there is. Just multiply the numerator out. Then split it up and integrate.

Oh wow... Thanks for the help. I feel a little silly right now.
 

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