Evaluate Trig Sub Homework: Int from Infty to -Infty

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Homework Help Overview

The discussion revolves around evaluating the integral \(\int_{\infty}^{-\infty} \frac{dz}{(z^2+x^2)^{3/2}}\) using trigonometric substitution. Participants are exploring the implications of the substitution and the behavior of the integral over the specified bounds.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of trigonometric substitution, specifically \(z = x \tan(\theta)\), and the resulting transformation of the integral. There are questions about the bounds of integration and the interpretation of the expression raised to the power of \(3/2\). Some participants express confusion about the limits and how they affect the evaluation.

Discussion Status

The discussion is ongoing, with participants attempting to clarify the setup of the problem and the implications of the trigonometric substitution. Some guidance has been offered regarding the bounds and the nature of the integral, but there is no clear consensus or resolution yet.

Contextual Notes

Participants are working under the constraints of homework rules, focusing on understanding the evaluation process rather than providing complete solutions. There is mention of needing to adapt the approach for different bounds in a related problem.

Winzer
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Homework Statement


Having trouble evaluating:
[tex]\int_{\infty}^{-\infty} \frac{dz}{(z^2+x^2)^(3/2)}[/tex]

Homework Equations


Trig sub
[tex]z=xtan(\theta)[/tex]

The Attempt at a Solution


comes down to:
[tex]\int_{x\frac{\pi}{2}}^{-x\frac{\pi}{2}} cos(\theta) d\theta[/tex]
goes to
[tex]sin(\theta)[/tex] from [tex]x\frac{\pi}{2} \longrightarrow -x\frac{\pi}{2}[/tex]
ehh!?
 
Last edited:
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You can change the bounds differently. Think about it, as long x is some constant, and z approaching negative infinity and positive infinity, the tan theta has to be...
 
mm...just [tex]\frac{\pi}{2}[/tex]
 
is that supposed to be to the 3/2 power or is that a constant multiplying the denominator?
 
rocophysics said:
is that supposed to be to the 3/2 power or is that a constant multiplying the denominator?
Sorry it is that quantity raised to the (3/2)
 
Basically I am trying to figure out how this book got
[tex]\frac{z}{x^2\sqrt(z^2+x^2)}[/tex] with bounds from infinity to -infinity.
They then go on to get [1--1]=2.

I have to do this for a similar problem except my bounds will be L to -L.
the answer is: [tex]\frac{L}{x^2 \sqrt(L^2+x^2)}[/tex] I do not know how.
Trying to remember how to do bounds on trig subs.
 
Anyone?
 
Winzer said:
Basically I am trying to figure out how this book got
[tex]\frac{z}{x^2\sqrt(z^2+x^2)}[/tex] with bounds from infinity to -infinity.
They then go on to get [1--1]=2.

I have to do this for a similar problem except my bounds will be L to -L.
the answer is: [tex]\frac{L}{x^2 \sqrt(L^2+x^2)}[/tex] I do not know how.
Trying to remember how to do bounds on trig subs.

maybe divide top and bottom by z. then plug in the limits from infinity to -infinity

I get zero? I get (1/x^2)-(1/X^2)
 
Winzer said:
Basically I am trying to figure out how this book got
[tex]\frac{z}{x^2\sqrt(z^2+x^2)}[/tex] with bounds from infinity to -infinity.
They then go on to get [1--1]=2.

I have to do this for a similar problem except my bounds will be L to -L.
the answer is: [tex]\frac{L}{x^2 \sqrt(L^2+x^2)}[/tex] I do not know how.
Trying to remember how to do bounds on trig subs.

Integrating with respect to z or x? State the exact question given to you please.
 

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