Evaluating a Finite Sum to a Closed Form Expression

aaaa202
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I have a finite sum of the form:

n=1Nexp(an+b√(n))

Is there any trick to evalute this sum to a closed form expression? e.g. like when a finite geometric series is evaluated in closed form.
 
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aaaa202 said:
I have a finite sum of the form:

n=1Nexp(an+b√(n))

Is there any trick to evalute this sum to a closed form expression? e.g. like when a finite geometric series is evaluated in closed form.
Not here.
You can often get a clue by treating a sum as an integral. In this case you can break it into a difference of two integrals. The first corresponds to ∑n=1Nexp(an), which is simply the sum of a geometric series, but the second becomes constant*∫eax2.dx.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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