Evaluating a Finite Sum to a Closed Form Expression

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SUMMARY

The discussion focuses on evaluating the finite sum of the form ∑n=1Nexp(an+b√(n)) to a closed form expression. A key insight is that this sum can be approached by treating it as an integral, specifically breaking it into two parts: the first part corresponds to the sum of a geometric series, ∑n=1Nexp(an), while the second part involves a constant multiplied by the integral ∫eax².dx. This method provides a systematic way to derive a closed form for the given sum.

PREREQUISITES
  • Understanding of finite sums and series
  • Familiarity with exponential functions and their properties
  • Basic knowledge of integral calculus
  • Experience with geometric series evaluation
NEXT STEPS
  • Research techniques for evaluating integrals, specifically ∫eax².dx
  • Study the properties and applications of geometric series
  • Explore methods for approximating sums using integrals
  • Learn about advanced summation techniques in mathematical analysis
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Mathematicians, students studying calculus, and anyone interested in advanced summation techniques and integral approximations.

aaaa202
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I have a finite sum of the form:

n=1Nexp(an+b√(n))

Is there any trick to evalute this sum to a closed form expression? e.g. like when a finite geometric series is evaluated in closed form.
 
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aaaa202 said:
I have a finite sum of the form:

n=1Nexp(an+b√(n))

Is there any trick to evalute this sum to a closed form expression? e.g. like when a finite geometric series is evaluated in closed form.
Not here.
You can often get a clue by treating a sum as an integral. In this case you can break it into a difference of two integrals. The first corresponds to ∑n=1Nexp(an), which is simply the sum of a geometric series, but the second becomes constant*∫eax2.dx.
 

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