Evaluating a Surface Integral: xze^y i -xze^y j +z k

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SUMMARY

The discussion focuses on evaluating the surface integral of the vector field F(x,y,z) = xze^y i - xze^y j + z k over the surface defined by the plane equation x + y + 2z = 2 in the first octant, oriented downwards. The integral is expressed as ∫∫σ F dS = ∫∫R (xze^y i - xze^y j + z k)(z_x i + z_y j - k) dA, leading to the formulation of the integral as ∫∫R (x^2z^2e^y - xyz^2e^y - z) dA. The user seeks confirmation on the correctness of their approach and inquires about substituting for z in the integral.

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Homework Statement



Evalute the surface integral

Homework Equations



F(x,y,z)=xze^y i -xze^y j +z k for the surface is partof the plane x+y+2z=2 in the first octant and orientated downwards

The Attempt at a Solution



[itex]\displaystyle \int \int_{\sigma} F dS=\int \int_R (xze^y i -xze^y j +z k)(z_x i+ z_y j -k) dA=\int \int_R (x^2z^2e^y-xyz^2e^y-z) dA[/itex]


Is this correct so far...if so have I to substitute for z and put in above integral. Looks like a difficult integral...?
 
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Something like

[itex]\displaystyle \int \int_{\sigma} F dS=\int \int_R (xze^y i -xze^y j +z k)(z_x i+ z_y j -k) dA=\int \int_R (x^2z^2e^y-xyz^2e^y-z) dA \implies[/itex]

[itex]\displaystyle \int \int_{\sigma} F dS=\int \int_R (x^2(\frac{2-x-y}{2})^2 e^y-xy(\frac{2-x-y}{2})^2 e^y-(\frac{2-x-y}{2})) dA[/itex].?

Posted at this link also. Will notify both forums of any responses. Thanks
http://www.freemathhelp.com/forum/threads/73614-surface-integral
 
Last edited:

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