Exam coming soon, need help with this question

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In summary, the two bodies are moving in a straight line with a constant velocity of 40m/s and an acceleration of 2m/s2. The question asks how long it takes for the second body, which starts at rest, to catch up with the first body and how far from the starting point this occurs. To solve this, we can use the equations v=u+at, s=ut+0.5at^2, and v^2=u^2+2as. We can also draw a rough graph to visualize the situation. The 10 seconds mentioned in the problem is the time difference between when the first body starts moving and when the second body starts accelerating.
  • #1
milan.007
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Exam coming soon, need urgent help with this question!

Homework Statement


A body leaves a point A and moves in a straight line with a constant velocity of 40m/s. Ten seconds later another body which is at rest at A is given an accelleration of 2m/s2 and moves in the same direction as the first body. How long does it take the second body to catch up with the first? How far from A does this occur?


Homework Equations





The Attempt at a Solution

 
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  • #2
Use these:
v=u+at
[tex]s=ut+0.5at^2[/tex]
[tex]v^2=u^2+2as[/tex]

and come back with specific doubts.:rolleyes:
 
  • #3
I know I am suppsed to use those equations but i don't know how? I don't know what to do with the 10 seconds.
 
  • #4
Draw a picture!

milan.007 said:
I don't know what to do with the 10 seconds.

Sometimes a picture makes things clearer.

Draw it for yourself (only roughly) on a graph (distance against time).

Then I think you'll see where the 10 seconds comes in. :smile:
 

Related to Exam coming soon, need help with this question

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