Examples of u_n and v_n Sequences with Finite Sum | Help with Homework"

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Homework Help Overview

The discussion revolves around finding sequences \( u_n \) and \( v_n \) that satisfy specific conditions related to their sums and relationships. The sequences must be non-negative and adhere to the inequality \( u_{n+1} \leq u_n + v_n \) for all \( n \), with the sum \( \sum_{n=1}^{\infty} v_n \) being finite.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore various examples for \( u_n \) and \( v_n \), with some suggesting specific forms like \( v_n = 1/2^n \) and \( u_n = 1/n \). Others express a desire for both sequences to be non-zero and question the implications of the conditions provided.

Discussion Status

The discussion is ongoing, with participants sharing potential examples and questioning the requirements for the sequences. Some guidance has been offered regarding the selection of summable sequences, but there is no consensus on the final forms of \( u_n \) and \( v_n \).

Contextual Notes

Some participants note the difficulty in finding appropriate sequences that meet the criteria while also adhering to the theorem mentioned, which relates to the existence of limits under certain conditions.

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Homework Statement


Please help me find examples.

u_n\subset [0,\infty) and v_n\subset [0,\infty) such that
u_{n+1}\leq u_n+v_n for all n and \sum_{n=1}^{\infty}v_n
is finite.


Homework Equations





The Attempt at a Solution

 
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Say you take u_n=0 for all n...
 
morphism said:
Say you take u_n=0 for all n...

I want to find v_n\neq 0 ,u_n\neq 0 for all n
 
My advice is to first pick a nice, summable v_n.
 
Please help me find examples.

u_n\subset [0,\infty) and v_n\subset [0,\infty) such that
u_{n+1}\leq u_n+v_n for all n and \sum_{n=1}^{\infty}v_n
is finite.

In fact, this is a theorem which say that

u_n\subset [0,\infty) and v_n\subset [0,\infty) such that
u_{n+1}\leq u_n+v_n for all n
If \sum_{n=1}^{\infty}v_n
is finite then \displaystyle{\lim_{n\rightarrow \infty}u_n} exists

then I want to find u_n which dificult to find lim in order to guarantee
this therem is well better than MCT because this therem is generalization of MCT.
 
Why don't you want to put in some effort?

Pick a summable (v_n), like say v_n = 1/2^n. Now pick any decreasing (u_n), like u_n = 1/n.
 

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