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Excess electrons on a lead sphere

  1. Sep 21, 2007 #1
    1. The problem statement, all variables and given/known data
    Excess electrons are placed on lead sphere with mass m=8.00g so that net charge becomes q=-3.20*10^-9 C.

    How many excess electrons are there per lead atom?

    2. Relevant equations

    3. The attempt at a solution

    Have found:

    number of excess electrons= 2.00*10^10

    atomic number of lead=82
    atomic mass of lead= 207g/mol
  2. jcsd
  3. Sep 21, 2007 #2


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    how many lead atoms are in a lead sphere of 8.00g ?
  4. Sep 21, 2007 #3
    207g=6.623x10^23 atoms... 8g =? atoms. You have the excess electrons, and now the number of atoms of lead in an 8 g sphere...
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