Excess electrons on a lead sphere

Click For Summary
SUMMARY

The discussion centers on calculating the number of excess electrons on a lead sphere with a mass of 8.00 grams and a net charge of -3.20 x 10^-9 C. The solution reveals that the number of excess electrons is 2.00 x 10^10. Given that the atomic number of lead is 82 and its atomic mass is 207 g/mol, the number of lead atoms in the sphere is derived using Avogadro's number, leading to a precise calculation of excess electrons per lead atom.

PREREQUISITES
  • Understanding of basic electrostatics and charge calculations
  • Familiarity with atomic structure, specifically lead's atomic number and mass
  • Knowledge of Avogadro's number and its application in mole calculations
  • Basic proficiency in unit conversion and dimensional analysis
NEXT STEPS
  • Research the concept of charge quantization and its implications in electrostatics
  • Learn about Avogadro's number and its significance in chemistry
  • Explore the relationship between mass, moles, and number of atoms in different elements
  • Investigate the properties of lead and its applications in various fields
USEFUL FOR

Students studying physics or chemistry, educators teaching electrostatics, and anyone interested in the properties of materials and atomic calculations.

save the ape
Messages
1
Reaction score
0

Homework Statement


Excess electrons are placed on lead sphere with mass m=8.00g so that net charge becomes q=-3.20*10^-9 C.

How many excess electrons are there per lead atom?


Homework Equations





The Attempt at a Solution



Have found:

number of excess electrons= 2.00*10^10

atomic number of lead=82
atomic mass of lead= 207g/mol
 
Physics news on Phys.org
how many lead atoms are in a lead sphere of 8.00g ?
 
207g=6.623x10^23 atoms... 8g =? atoms. You have the excess electrons, and now the number of atoms of lead in an 8 g sphere...
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
1K
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K