Jason Louison
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jack action said:I don't see why not. Of course, the first function cannot depend on the last one, but you can compare the results where the answer of the first function must equal the answer of the last function ( ##\frac{x_1}{x_2} = 1## or ##x_1 - x_2 = 0## ).
I'll just use the equation that depends of volume a the start of the cycle, It seems to work pretty well, but now I need to find out how to simulate valve overlap!