Expanding ln isn't working for me

original equation: ln(0.2048x$\frac{5}{2}$)= -$\frac{5}{2}$

when i just raise this to e i get..

0.2048T$\frac{5}{2}$= -$\frac{5}{2}$

and then i can solve for x and get the right answer. but when i expand the logs..

ln(0.2048) + $\frac{5}{2}$ln(x)= -$\frac{5}{2}$

0.2048+$\frac{5}{2}$x=e-$\frac{5}{2}$

then i try to solve for x i don't get the right answer. what am i doing wrong?