darkar Messages 187 Reaction score 0 Thread starter Feb 11, 2006 #1 How do u expand f(x,y) = y^2/x^2 about the point (1,-1) ? up to and including quadratic term?
Zurtex Science Advisor Homework Helper Messages 1,118 Reaction score 1 Feb 11, 2006 #2 darkar said: How do u expand f(x,y) = y^2/x^2 about the point (1,-1) ? up to and including quadratic term? Have you ever used the taylor series on multi-variable functions before?
darkar said: How do u expand f(x,y) = y^2/x^2 about the point (1,-1) ? up to and including quadratic term? Have you ever used the taylor series on multi-variable functions before?
darkar Messages 187 Reaction score 0 Feb 11, 2006 #3 Not really, how? Have only done one variable so far.
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Feb 11, 2006 #4 The general term in a Taylor's series for f(x,y) about the point (a,b) is [tex]\frac{1}{(m+n)!}\frac{\partial^m f}{\partial x^m}\frac{\partial^n f}{\partial y^n}(x- a)^m(y- b)^n[/tex] (edited. Thanks, daveb) Last edited by a moderator: Feb 12, 2006
The general term in a Taylor's series for f(x,y) about the point (a,b) is [tex]\frac{1}{(m+n)!}\frac{\partial^m f}{\partial x^m}\frac{\partial^n f}{\partial y^n}(x- a)^m(y- b)^n[/tex] (edited. Thanks, daveb)
Hurkyl Staff Emeritus Science Advisor Gold Member Messages 14,922 Reaction score 28 Feb 11, 2006 #6 Bah, everybody likes to do it the hard way. f(x, y) is just a product of two things whose Taylor series you already know!
Bah, everybody likes to do it the hard way. f(x, y) is just a product of two things whose Taylor series you already know!