Expansion Work in Combustion Reactions: Liquid Water vs. Water Vapor

AI Thread Summary
In combustion reactions, the type of water produced—liquid or vapor—affects the expansion work generated. Higher expansion work is typically associated with the production of water vapor due to the greater volume of gas produced. However, enthalpy calculations indicate that reactions yielding liquid water result in higher PV work, as they have a more negative enthalpy change. The confusion arises from the relationship between enthalpy of formation and the energy released during combustion. Ultimately, understanding the thermodynamic principles governing these reactions is crucial for accurate predictions of expansion work.
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Expansion Work -- Still confused.

This is more of a general question regarding thermodynamics. If you have a combustion reaction, and it produces either liquid water or water vapor--which case results in higher expansion work? My enthalpy calculations show higher PV work for the reaction with liquid water as the product, but intuitively, I feel like the reaction producing water vapor would do more work because a greater amount of gas is produced.

Thanks in advance for your input!
 
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I guess I should specify. The way I calculated the enthalpy of combustion was by subtracting the enthalpies of formation for the reactants from those of the products--a generic way to get the enthalpy change for any reaction. However, since water (gas) has a higher Hf, the overall H of the combustion is also higher (less negative value). This suggests that the combustion of a compound to CO2 and H2O (g) actually releases less energy (i.e., less work can be done).

Please give me your input... Am I not justifying this correctly?
 
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