Expectation value in quantom mechanics (a general question)

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The discussion revolves around confusion regarding the calculation of expectation values in quantum mechanics, particularly for angular momentum operators Lx and Ly. The user initially applies the expectation value formula <ψ|A|ψ> to a wave function composed of multiple eigenstates but encounters difficulties when calculating uncertainty. They notice that the expectation value for Lx is often computed using the same eigenstate in both bra and ket, leading to a result of zero. The key point of contention is whether a wave function can be composed of different eigenstates, which the user believes should yield different results. Ultimately, the resolution lies in recognizing that the calculations differ based on the choice of eigenstates used in the expectation value expressions.
itaibh1
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Homework Statement


Hello, I'm a bit confused about the calculation of the expectation values. Normally, when I have a wave function of sort and I want to calculate the expectation value of some operator, I just insert it into the braket <ψ|A|ψ>, where ψ for example is a wave function composed out of eigenstates ψ=1/√3⋅(φ123)
and I will just multiply those accordingly.
My problem started when I was asked to calculate uncertainty for Lx and Ly, I keep seeing the expectation value it's being calculated like this:
Lx=1/2⋅<lm|L++L-|lm>=0, with both bra-ket are for the same state. I don't understand, why can't the wavefunction be one that is composed out of several different eigenstates?

Homework Equations

The Attempt at a Solution


When I calculated it at first, I did:
<Lx>=1/2⋅<lm|L++L-|l'm'>, which confused me even more, since this is actually a calculation for the Lx matrix elements. What am I doing wrong here?
 
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So far I see nothing wrong.
I keep seeing the expectation value it's being calculated like this:
Lx=1/2⋅<lm|L++L-|lm>=0, with both bra-ket are for the same state
So what you see there is that they calculate Lx for a state |lm> that is an eigenstate of both L2 and Lz.
Apparently you have a different state Ψ so you get something different. Where 's the contradiction you see ?
 

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