Expectation value of a dynamical variable problem.

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The discussion centers on why an extra phase factor cancels out in the context of expectation values of dynamical variables. It is clarified that the phase factor is multiplied by its conjugate, which is crucial because it is independent of the variable x. This independence means that when the operator acts on the wave function, the phase factor behaves like a constant, thus not affecting the derivative. If the phase factor were dependent on x, the product rule would apply, complicating the calculation. Ultimately, for the phase to not alter expectation values, it must commute with the operator involved.
Normalization
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Homework Statement


Why does the extra phase factor cancel out? Is it because you are multiplying the wave-function with the extra phase factor by its conjugate and if so, why should it matter that the extra phase factor is independent of x?

All relevant information, the solution and equation referred to in the solution is given below:

Prob18.jpg


Homework Equations



Given in picture

The Attempt at a Solution



See problem statement
 
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Normalization said:

Homework Statement


Why does the extra phase factor cancel out? Is it because you are multiplying the wave-function with the extra phase factor by its conjugate and if so, why should it matter that the extra phase factor is independent of x?

All relevant information, the solution and equation referred to in the solution is given below:

Prob18.jpg


Homework Equations



Given in picture

The Attempt at a Solution



See problem statement

Yes, the phase get multiplied by its conjugate. If the phase had had an x dependence then when the operator Q (which could contain d/dx) acts on ψ it could also change the phase factor.
 
Oh I see :) Because the phase factor is independent of x it acts as a constant on ψ so taking the derivative of one of the ψ's wouldn't affect the value of the phase factor, but if it was dependent of x one would need to use the product rule to take the partial of one of the psi's.
 
Normalization said:
Oh I see :) Because the phase factor is independent of x it acts as a constant on ψ so taking the derivative of one of the ψ's wouldn't affect the value of the phase factor, but if it was dependent of x one would need to use the product rule to take the partial of one of the psi's.

Right! The phase has to commute with the operator Q if it's not going to change expectation values.
 
Cool, thanks :D
 

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