Expected value and variance of these sums

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The expected value of the function x = a + b - 1, where both a and b have expected values of 0.5, is calculated to be 0. The expected value is derived from the equation 0.5 + 0.5 - 1, confirming that it equals 0. For the variance, if a and b are independent and each has a variance of 1/12, the variance of x is found to be 1/6, as variances of independent variables add together. The variance of a constant is zero, which is also noted in the discussion. This clarifies the basic concepts of expected value and variance in this context.
Dixanadu
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Hi guys,

Suppose I have the function
x = a + b -1
where a, b have expected values of 0.5 each. What is the expected value of x? is it 0.5 + 0.5 -1 = 0? or is it just 0.5 + 0.5?

Secondly, suppose the same equation as above, x = a + b -1. If the variance of both a and b is 1/12, what is the variance of x?

I know this is really basic but I just don't understand. Thanks guys!
 
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The expected value of x is 0, as you should expect. The expected value of a constant is its value.

If a and b are independent, the the variances just add, so the variance of x is 1/6. Note that the variance of a constant is 0.
 
Okay, thank you :)
 
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