Expected Value of Random Variables

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Homework Help Overview

The discussion revolves around calculating the expected value of a random variable X given its cumulative distribution function (cdf). Participants are exploring the relationship between the cdf and the probability mass function (pmf) to derive E(X).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to calculate E(X) from the cdf, expressing familiarity with the pmf but uncertainty about transitioning from the cdf. Some participants suggest considering the implications of the discontinuities in the cdf to derive the pmf.

Discussion Status

Participants are actively engaging with the problem, with one suggesting a potential pmf based on the cdf. There is a positive acknowledgment of this suggestion, indicating a collaborative exploration of the topic.

Contextual Notes

The discussion is framed within the context of homework help, with an emphasis on understanding the mathematical concepts rather than providing direct solutions.

Quincy
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Homework Statement


Consider a random variable X having cdf:

1, x ≥ 4,
3/4, 1 ≤ x < 4,
FX(x) = 1/2, 0 ≤ x < 1,
1/4, −1 ≤ x < 0,
0, x < −1.

Give the value of E(X).

Homework Equations





The Attempt at a Solution


I know how to calculate the value of E(X) given the probability mass function (E(X) = x1*p(x1) + x2*p(x2) + ...) but how do I calculate E(X) given the cdf?
 
Last edited:
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You can find the probability density (what you are referring to as the probability mass function) from the cdf. Think about what the discontinuous jumps in the cdf represent.
 
Hmm.. so would the pmf be:

0.25, x = -1
0.25, x = 0
0.25, x = 1
0.25, x = 4

?
 
Yup!
 

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