Explain the energy levels of Samarium-154

[JD_PM]

Homework Statement

Justify the energy levels of Samarium-154

Relevant Equations

Vibrational energy-Rotational energy

These are the experimental results for the energy levels of Samarium-154:

From 0+ to 8+ I recognize rotational energy:

$$E = \frac{l(l+1)\hbar^2}{2I}$$

But from there on I do not know how to justify the rest.

I have been reading that we sometimes get energy diagrams like above for even-even nucleus in the range 150-190. In such diagrams we can talk about new rotational bands, getting vibrational states and pair-breaking particle excitations.

I have been reading an interpretation of Erbium-164 (which is a similar case to Sm-154) from Krane but I still don't get it...

Thank you for your help.

 

[member 553083]

It is difficult to say exactly what is going on with the energy levels of Samarium-154 without more detailed information. However, based on the information provided, it is likely that the energy levels between 0+ and 8+ correspond to rotational energy levels, as you have suggested. The remaining energy levels may be due to other physical phenomena such as vibrational states, pair-breaking particle excitations, or other effects. For example, in Erbium-164, Krane suggests that the higher energy levels are the result of vibrational and rotational excitations of the nucleus. It is possible that similar physical effects are occurring in Samarium-154. To get a better understanding of the energy levels of Samarium-154, it would be necessary to have more detailed information about the nucleus, such as its structure and interactions.