B Explain Why (7÷4)÷(1÷2)=7÷4÷1×2 | Fractions

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Can someone please explain why the following equation is true:

(7 \div 4) \div (1 \div 2) = 7 \div 4 \div 1 \times 2

As in, why does the division become multiplication when the parentheses are removed?Thanks
 
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Dividing by something is the same as multiplying by the inverse (by definition), and the inverse of 1/2 is 2/1. Therefore, (7/4)/(1/2) = (7/4) * (2/1) = (7/4)*2/1 = ((7/4)/1)*2.
 
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Thanks!

mfb said:
Dividing by something is the same as multiplying by the inverse (by definition), and the inverse of 1/2 is 2/1. Therefore, (7/4)/(1/2) = (7/4) * (2/1) = (7/4)*2/1 = ((7/4)/1)*2.
 
eddie159 said:
Thanks!

I can't resist to say that ##a \div b## is an ugly and often confusing notation. Rather, we use ##\frac{a}{b}##
 
When we divide a fraction by another fraction, we have to multiply first fraction by the reciprocal of second fraction.
i.e. $$\dfrac{a}{b}\div \dfrac{m}{n}=\dfrac{a}{b}\times \dfrac{n}{m}$$
so $$(7\div 4)\div (1\div 2)=\dfrac{7}{4}\div \dfrac{1}{2}=\dfrac{7}{4}\times \dfrac{2}{1}$$
 
Math_QED said:
I can't resist to say that ##a \div b## is an ugly and often confusing notation. Rather, we use ##\frac{a}{b}##
I totally agree.
 
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Dividing a fraction by another fraction is same as multiplying reciprocal of another fraction. So,

##\dfrac{7}{4}\div\dfrac{1}{2}=\dfrac{7}{4}\times\dfrac{2}{1}=\dfrac{\dfrac{7}{4}}{1}\times2##

##\implies\dfrac{7}{4}\div\dfrac{1}{2}=\dfrac{14}{4}##

##\implies\dfrac{7}{4}\times\dfrac{2}{1}=\dfrac{14}{4}##

##\implies\dfrac{\dfrac{7}{4}}{1}\times2=\dfrac{14}{4}##
 
You have a lot of extra work here that isn't needed.
Deepak suwalka said:
Dividing a fraction by another fraction is same as multiplying reciprocal of another fraction. So,

##\dfrac{7}{4}\div\dfrac{1}{2}=\dfrac{7}{4}\times\dfrac{2}{1}##
##=\frac 7 2##
Done...
Deepak suwalka said:
##=\dfrac{\dfrac{7}{4}}{1}\times2##

##\implies\dfrac{7}{4}\div\dfrac{1}{2}=\dfrac{14}{4}##

##\implies\dfrac{7}{4}\times\dfrac{2}{1}=\dfrac{14}{4}##

##\implies\dfrac{\dfrac{7}{4}}{1}\times2=\dfrac{14}{4}##
With all of this extra, unnecessary work, you at least could have simplfied your final result.
 
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