Explain why this function is discontinuous

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The discussion centers on the discontinuity of a piecewise function at x = -1. The limit of the function as x approaches -1 is incorrectly calculated by some participants, leading to confusion about its continuity. The correct limit should be 2, as per the textbook, but some argue that it appears to be 1 based on their calculations. The disagreement highlights a misunderstanding in factoring the denominator of the function. Ultimately, the function is classified as discontinuous at x = -1 due to the mismatch between the limit and the function's value at that point.
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Homework Statement


Using the test for continuity at a point, explain why each function is discontinuous at the given x-value. Classify each discontinuity.

the question is a piecewise function.

i(x)={(x^2+5x+4)/(x^3+1), x=/= -1
{2, x=-1

this is all one piece wise function.


The Attempt at a Solution



I first can say that the function exists and the limit exists just by glance. At x=-1 for the first piece, it is indeterminent. So I factor the first piece and end up with:

lim (x+4)/(x^2+x+1)
x->-1

subbing in a negative one I get 3.

but the back of the book says:

lim i(x) =2
x->-1

I'm not sure how.
 
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you should get x^2-x+1 and not x^2+x+1. But I get 1 instead of 2 still...
 
nvm, the book must be wrong..
 
Well, for one thing you factored the denominator wrong. Are you sure the back of the book doesn't say lim(i(x))=1 as x->-1?
 
I think the book's wrong seeing as it wants you to show why the function is not continuous, when its answer would actually show that it is continuous at x=1... I think rock freak is right on this one.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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