Exploding Capacitor: Calculating Voltage for a 100uF 10V Capacitor

  • Thread starter Thread starter Momosaida
  • Start date Start date
  • Tags Tags
    Capacitors Voltage
Click For Summary
A 100uF 10V electrolytic capacitor can theoretically explode if reverse-biased, but practical outcomes may vary. Connecting a 9V battery backwards did not cause an explosion, raising questions about whether the connection was indeed reversed. The discussion highlights that while any voltage can potentially lead to failure, the actual results depend on various factors, including the capacitor's condition and the voltage applied. Participants caution against experimenting for safety reasons, emphasizing the potential for waste and disruption in educational settings. Overall, the thread underscores the risks associated with reverse biasing capacitors.
Momosaida
Messages
5
Reaction score
0
How many volts would i need to make a 100uF 10V capacitor explode if i plugged it in backwards?
 
Engineering news on Phys.org
Theoretically the moment you reverse bias the polarized cap, the cap will explode. You can try it out, wear goggles.
 
If it is electrolytic, which you didn't say, then practically any voltage will cause it to explode. As Corneo says it easy to try...and it's also a good way to make lecturers/teachers/lab technicians/fellow students rather cross with you - both for wasting caps and making them jump every few minutes :P
 
Yes the capacitor is electrolytic. But when I connected a 9V battery to it backwards, it didn't explode. Why?
 
Last edited:
Are you sure it was backwards?...I know it's obvious but some people, even degree level students, get that wrong. 9V should be plenty to do the job, unless it's a huuge capacitor it might be a bit harder. I can't say I have every studied the ins and outs of reversing caps! :)
 
I'm uncomfortable with this thread. Momosaida -- there are better things for you to be doing with your time instead of trying to blow up capacitors.

Thread locked.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

Similar threads

  • · Replies 4 ·
Replies
4
Views
546
Replies
1
Views
1K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 78 ·
3
Replies
78
Views
6K
  • · Replies 6 ·
Replies
6
Views
616
  • · Replies 49 ·
2
Replies
49
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K