Explosion of a moving mass into two parts.

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Discussion Overview

The discussion revolves around a hypothetical scenario where a moving mass M, traveling at a velocity of 0.5c, explodes into two fragments, A and B. Participants explore the implications of this explosion on the velocities and energies of the fragments, considering the principles of conservation of momentum and energy, particularly in the context of special relativity.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant poses a problem about a moving mass M exploding into two fragments, A and B, and questions how to calculate their final velocities.
  • Another participant notes that additional information, specifically the kinetic energy of the fragments after the explosion, is necessary to solve the problem.
  • There is a suggestion that the system could be analyzed in the rest frame of the mass and then transformed to the moving frame using relativistic velocity addition.
  • Concerns are raised about what causes the fragments to move apart, emphasizing that without energy from the explosion, the fragments would not separate.
  • Some participants express confusion over the problem statement, suggesting that the rest masses of the fragments must be specified to allow for movement, and that the total rest mass of the fragments must be less than M for the system to conserve energy and momentum.
  • Participants discuss the need for additional energy to be added to the system for the fragments to separate, and outline equations for energy and momentum conservation that could be used to determine the velocities of the fragments.

Areas of Agreement / Disagreement

Participants generally agree that the problem lacks sufficient information and that the conservation of energy and momentum must be considered. However, there is no consensus on how to define the problem clearly or on the necessary conditions for the fragments to move apart.

Contextual Notes

Limitations include the incomplete problem statement, the need for specific rest masses for the fragments, and the requirement for additional energy for the fragments to separate. The discussion also highlights the complexity of applying relativistic principles in this context.

randombill
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I figure this problem will not be easily solvable which is why I'll ask.

Basically a moving mass M with a velocity along the x direction of .5c explodes into two fragments. Fragment A moves to the -x and fragment B moves to the +x. The sum of the mass is 1/4A + 3/4B = M. What are the final velocities of the two fragments?

I made this question up. Most physics books tell you the Mass is at rest initially but what would happen if it moves and then explodes. What are the calculations for it?
 
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You haven't supplied enough information - need energy (kinetic energy of fragments) after explosion. Once you have that you can carry out the calculation assuming it started at rest. Then add the initial velocity to both pieces, making sure you take into account special relativity if the fragments are moving fast.
 
mathman said:
need energy (kinetic energy of fragments) after explosion.

But that would require the velocity as well. Couldn't the system be solved in the rest frame and then moved over into the moving frame. I'm assuming that in the rest frame the velocities of the two fragments can be found along with the relativistic KE and then moving the system over into a moving frame of reference is just a relativistic velocity addition?I just wanted to point out that the explosion does not add any momentum to the two fragments and that the system is conserved. Let's just say that the two parts move apart instead of "explode".
 
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What makes them move apart? Although the total momentum in the c.m. coordinate system is zero, how much each piece has depends on the energy resulting from the explosion.
If there is no energy, they won't move apart at all.
 
mathman said:
What makes them move apart? Although the total momentum in the c.m. coordinate system is zero, how much each piece has depends on the energy resulting from the explosion.
If there is no energy, they won't move apart at all.

I understand, its because of the first reason you explained. I did make the problem up so its not something that's from a book, but thanks for the help.
 
One issue is your problem statement is incomplete and confusing. A possible guess (but I shouldn't have to guess, and this may not be what you meant) is:

I have an object with rest mass M. It splits by some unspecified process into objects A and B, whose rest masses are 1/4M and 3/4M, respectively.

If this is what you meant (but didn't say - read your first post), the problem is already determined. In the rest frame of M, there is no available energy given the masses of the pieces. So A and B remain where they are, just separated by imagination. This is they way it will look in any other frame relative to which M is moving: an imaginary crack has appeared in M.

To allow A and B to move in the COM frame, you must specify rest masses for them whose total is less than M.

Maybe you meant something different, but I couldn't make head or tail of what that might be.

[Note, you could make this well defined and have something closer to what your intent might be if you specified e.g. that:

rest mass of A= .99*.25 M, rest mass of B=.99*.75M. The problem would then be fully determined given all your other constraints.]
 
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PAllen said:
One issue is your problem statement is incomplete and confusing. A possible guess (but I shouldn't have to guess, and this may not be what you meant) is:

I have an object with rest mass M. It splits by some unspecified process into objects A and B, whose rest masses are 1/4M and 3/4M, respectively.

If this is what you meant (but didn't say - read your first post), the problem is already determined. In the rest frame of M, there is no available energy given the masses of the pieces. So A and B remain where they are, just separated by imagination. This is they way it will look in any other frame relative to which M is moving: an imaginary crack has appeared in M.

To allow A and B to move in the COM frame, you must specify rest masses for them whose total is less than M.

Maybe you meant something different, but I couldn't make head or tail of what that might be.

[Note, you could make this well defined and have something closer to what your intent might be if you specified e.g. that:

rest mass of A= .99*.25 M, rest mass of B=.99*.75M. The problem would then be fully determined given all your other constraints.]


No you're right, I just assumed the two masses moved apart with 1/4M and 3/4M which wouldn't work since something has to make that happen. So obviously if the system is conserved then (1/4M and 3/4M) < M and to make it conserved some extra energy must be added to the system to make the two parts move away from each other.
 
randombill said:
No you're right, I just assumed the two masses moved apart with 1/4M and 3/4M which wouldn't work since something has to make that happen. So obviously if the system is conserved then (1/4M and 3/4M) < M and to make it conserved some extra energy must be added to the system to make the two parts move away from each other.

Just to outline how it is fully specified as long as you give some rest mass to A and B such that: A + B < M [letting A and B stand for the given rest masses].

Then you have, by energy conservation (using frame where M is initially at rest):

Mc^2 = E1 + E2 [E1 and E2 are total energy for A and B respectively: KE + rest energy]

and by momentum conservation:

E1^2/c^4 - A^2 = E2^2/c^4 - B^2

These two equations determine E1 and E2 in terms of A, B, and M. Then you have momentum (absolute value) of A and B (same, different direction) by:

p^2 = E1^2/c^2 - A^2 c^2

Then v1 = -p/√(A^2 + p^2/c^2)
v2 = p/√(B^2+p^2/c^2)

Then using velocity addition, you get the velocities in your chosen frame where M is moving at .5c.

----

I'll even give you that:

E1 = (c^2/2M)( M^2 - (B^2 - A^2))

E2 = Mc^2 - E1

Then just plug in whatever numbers you want.
 
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