Exponential growth of populations (Q=Ae^kt)

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Homework Help Overview

The discussion revolves around the exponential growth model of a rabbit population, represented by the equation N=80e^(0.02t), where N is the population at time t in days. The specific question is to determine the time required for the population to reach 500 rabbits.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the manipulation of the exponential growth equation to isolate the variable t. There are attempts to convert the equation into a logarithmic form, with some confusion regarding variable representation.

Discussion Status

The discussion is ongoing, with participants providing guidance on isolating the exponent and using logarithms. There is recognition of errors in variable usage and attempts to clarify the correct approach to solving the equation.

Contextual Notes

Some participants express uncertainty about the correctness of their working and the application of the formula, indicating a need for further clarification on the steps involved in solving the problem.

Alistair
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Homework Statement


The number of rabbits in a colony is given by N=80e^(0.02t) where t is in days.
c) After how many days will there be 500 rabbits?

N=500
A=80
k=0.02
t=?

Homework Equations


(ln being the exponential logarithm)
Q=Ae^kt
and possibly the conversion formula: ln y = x --> y=e^x

The Attempt at a Solution



what i tried was coverting Q=Ae^kt to A ln Q=kt
Then divided both sudes by x to give:

A ln Q = t
k


Which after substitution looked like this:

80 ln 500 = t
0.02

Which gave t=24,858 days.
where as the answer is 92 days...
 
Last edited:
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Alistair said:

Homework Statement


The number of rabbits in a colony is given by N=80e^(0.02t) where t is in days.
c) After how many days will there be 500 rabbits?

N=500
A=80
k=0.02
t=?

Homework Equations


(ln being the exponential logarithm)
Q=Ae^kt
and possibly the conversion formula: ln y = x --> y=e^x

The Attempt at a Solution



what i tried was coverting Q=Ae^kt to A ln Q=xt
Then divided both sudes by x to give:

A ln Q = t
x
This equation is wrong. Perhaps you are getting confused with your variables; there's no reason to introduce x, stick with A, k and t and try again.
 
marcusl said:
This equation is wrong. Perhaps you are getting confused with your variables; there's no reason to introduce x, stick with A, k and t and try again.

Yeah i ment k not x.
in my maths book in the examples it has x. but it still doesn't work with k in there... :frown:
 
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.
 
danago said:
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.

i don't know how dividing both sides by 80 will make it easier or alter the answer in any way...
i want to know if there is a problem with my working. I am not sure if it is even the right formula...
 
Alistair said:
Yeah i ment k not x.
in my maths book in the examples it has x. but it still doesn't work with k in there... :frown:
If you really believe that using the letter "x" gives you a different equation that using the letter "k", you need to review basic algebra!

danago said:
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.

Alistair said:
i don't know how dividing both sides by 80 will make it easier or alter the answer in any way...
i want to know if there is a problem with my working. I am not sure if it is even the right formula...

You have already been told that there is a problem with your "working"!

You are given the formula [itex]N= 80e^{0.02t}[/itex] so of course, that the correct formula. You are also told that N= 500 so the equation you want to solve is [itex]80 e^{0.02t}= 500[/itex]. Surely, it would be an obvious first step to divide both sides by 80? After you have done that take the natural logarithm of both sides.
 
ok got it.
500 = 80e^0.02t
goes to
ln 6.25 = t
0.02
 
Okay, now, what is your answer to the question?
 

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