How Can We Prove This Exponential Identity?

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The discussion centers on proving the identity involving the exponential function and its Taylor series. The left side represents the Taylor series for the exponential function, while the right side is defined through limits involving binomial coefficients. A correction was made to clarify the middle formula, showing it as the binomial expansion. As N approaches infinity, each term in the sum converges to y^r/r!. The conversation highlights the need to ensure the limits align properly to establish the equivalence of both sides.
muzialis
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Hi All,

I am struggling to prove the following identity

$$ 1 + y + \frac{1}{2!}y^2 + \frac{1}{3!}y^3 + \dots = lim_{N \to \infty} \sum_{r=0}^{N} \frac {N!}{r! (N-r)!} \frac{y}{N}^{r} = lim_{N \to \infty} (1 + \frac{y}{N})^N $$



any hint would the most appreciated. I understand the left-most term is the Taylor series for the exponential function, and the right-most term is also used as a definition of such function, yet I would like to know how the two are explicitly shown to be equivalent.

Thanks as usual
 
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muzialis said:
Hi All,

I am struggling to prove the following identity

$$ 1 + y + \frac{1}{2!}y^2 + \frac{1}{3!}y^3 + \dots = lim_{N \to \infty} \sum_{r=0}^{N} \frac {N!}{r! (N-r)!} \frac{y}{N}^{r} = lim_{N \to \infty} (1 + \frac{y}{N})^N $$
any hint would the most appreciated. I understand the left-most term is the Taylor series for the exponential function, and the right-most term is also used as a definition of such function, yet I would like to know how the two are explicitly shown to be equivalent.

Thanks as usual
There is a typo in the middle formula. It should be: ## \lim_{N \to \infty} \sum_{r=0}^{N} \frac {N!}{r! (N-r)!} (\frac{y}{N})^{r}##.

It is then easy to see that this is the binomial expansion of the right side.
One also sees that for each fixed ##r##, the ##r##-term in the middle sum tends to ##y^r/r!## as ##N \to\infty##.

It remains to convince oneself that everything works out with the limits.
 
Last edited:
Erland,
many thanks for pointing this out, I am a little bit closer now to understanding, many thanks
!
 

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