Exponential Theory: Explaining e^(-2 ln |x+1|) = e^ln [1/(x+1)^2]

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Homework Help Overview

The discussion revolves around the equation e^(-2 ln |x + 1|) = e^ln [1/(x + 1)^2], focusing on the properties of logarithms and their application in simplifying expressions.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between logarithmic properties and the transformation of the given equation. Questions arise regarding the notation used and its standardization in different contexts.

Discussion Status

The discussion includes attempts to clarify the logarithmic rules involved and the notation used. Some participants express confusion over the notation "alog" and seek confirmation on its meaning, while others provide insights into more commonly used forms of logarithmic expressions.

Contextual Notes

There is mention of varying notation standards in different mathematical communities, which may affect understanding. Participants also reference the need for clarity in mathematical communication.

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e ^ (-2 ln |x + 1|) = e ^ ln [1 / (x + 1)^2]

how can this happen?
can anyone explain to me the process of this equation..
 
Last edited:
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Nice how you absolutely did not try to hide the fact that you copied this from another forum.

The answer to your question: it is a known calculation rule for logarithms that
y alog(x) = alog(xy)
for any number a.
 
CompuChip said:
Nice how you absolutely did not try to hide the fact that you copied this from another forum.

The answer to your question: it is a known calculation rule for logarithms that
y alog(x) = alog(xy)
for any number a.

I haven't see notation like that before. Is alog supposed to represent the log base a of something?

The notation that is used more often for this property of logarithms, I believe, is this:
loga (xy) = y loga(x)
 
Thanks Mark44 =)
 
Mark44 said:
I haven't see notation like that before. Is alog supposed to represent the log base a of something?

The notation that is used more often for this property of logarithms, I believe, is this:
loga (xy) = y loga(x)

Right, sorry.
Where I come from alog is standard notation.
But that is what I meant.
 
I figured that's what it meant, but it's something I haven't run across it before.
 

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