Exponential word problem (i think)

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The discussion revolves around solving an exponential decay problem related to population decline. The population of an endangered species decreases by 25% annually, starting from 7500, and the goal is to determine how long it will take to reach a population of 4000. Participants suggest using the exponential decay formula P(t) = Ce^(kt) and discuss alternative forms like P = P_0 (3/4)^n for simplicity. There is a debate about whether to use calculus methods or simpler algebraic approaches, with a final confirmation that the time required is approximately 2.185 years. The thread also includes a note about proper posting etiquette in the forum.
Jacobpm64
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I'm not sure if this is calculus, but it is like a review in my calculus class.

Suppose that in any given year, the population of a certain endangered species is reduced by 25%. If the population is now 7500, in how many years will the population be 4000?

I've known how to do this before. I just forgot how to set it up. I'm pretty sure it's with exponents though. Please help.
 
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If it appeared as a question for calculus review, then they probably want you to proceed like this: You know the population can be descrided by an exponential equation of the form
P(t)=Ce^{kt}
for unknown constants C and k. Knowing the initial population will allow you to solve for C. Knowing the population a year later will let you solve for k. Then solve for time in the equation by taking ln's. Plug in the population you want and get the time it takes.
 
so let's see..
P(t) = 4000
C = 7500
e = the constant 2.718 etc.
k = what's k? I'm not sure how to do it since it's decay...?
t = what I'm solving for

so what is k?
 
Jacobpm64 said:
P(t) = 4000
Not exactly:
P(t)=7500e^{kt}
And in one year the population will be reduced by 25%, so:
P(1)=7500-.25*7500=5625=7500e^{k*(1)}
So now you can solve for k.
 
It might be easier to start with

P = P_0 \left( \frac {3}{4} \right)^n

where n is the number if years.
 
Tide said:
It might be easier to start with
P = P_0 \left( \frac {3}{4} \right)^n
where n is the number if years.
Yeah, I was thinking that too, but when I did that in high school calc class I remember my teacher took off points because she said "This is calculus class, solve the problem with calculus". They are probably trying to teach exponentials with this problem, but its good to know how to do it both ways.
 
2.1850811 years?

I believe so.. confirmation?

and thanks a lot :)
 
Jacobpm64 said:
2.1850811 years?
I believe so.. confirmation?
and thanks a lot :)
That's right.
 
This was also posted under "homework".


1) Please do not post the same thing in two different places.

2) There is a "sticky" thread at the top of this area that says this is NOT the right place to post homework problems.
 
  • #10
yeah, sorry about that, it won't happen again.. i noticed that sticky after i posted this one.. so i reposted in homework.. all of my future ones will go in homework.. thanks for the help, nonetheless
 

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