Express Max height in terms of g and T? ?

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Homework Help Overview

The discussion revolves around expressing the maximum height of a projectile in terms of gravitational acceleration (g) and time (T). Participants are exploring the relationship between initial velocity, time, and height in a physics context.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the maximum height using the formula involving initial vertical velocity and gravitational acceleration. Some participants question the role of initial velocity and its sign in determining the maximum height.

Discussion Status

Participants are actively discussing the conditions for maximum height, including the velocity at that point and the implications of the signs of initial velocity and gravitational acceleration. There is a mix of interpretations regarding the definitions and assumptions involved.

Contextual Notes

There is a mention of the need to consider the initial vertical velocity as a constant rather than a variable, and the discussion includes the importance of the signs of the variables involved in the context of projectile motion.

scke0803
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Express Max height in terms of g and T?!?

I need to express the y_max in terms of g and T...

do i need to put in my V_0y value? or leave it as a variable?









i've tried V_0y*T + 1/2gT^2
 
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Vo is not a variable, it is constant. Your formula is correct for the height at time T. You have to find the time when the body reaches it maximum height and does not rise any more. What is its velocity at that instant?

ehild
 


Velocity at maximum height is 4.229 m/s
 


So it moves further upward. Why is it maximum height then?
Try to throw up something and watch the velocity.

And mind the signs. There is a maximum height if Vo points upward (and g downward) . Vo and g have to be of opposite signs. ehild
 
Last edited:

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