Determine the equivalent impedance of the following network:
(My bad, the element at the far right where the j2ohm is was supposed to be an inductor, fixed now. The numbers are correct too.)
R(series) = R1 + R2?
R(parallel) = [ (1/R1) + (1/R2) ]-1
except with impedance now
The Attempt at a Solution
Not sure if I can do algebra with the imaginary components...
but the right branch would simplify to
(4Ω - j4Ω/3)
Then this is in parallel with j4Ω, simplifying to (12Ω + j4Ω + j12Ω)/(j4Ω(12Ω - j4Ω)).
All I want to know, is if this is really the right track? Can I really algebraically manipulate the imaginary components like this (maybe I Just need to review algebra now)? Any other tips would be helpful, thanks.
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