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Circuit (equivalent resistance)

  • #1
5
0

Homework Statement


Find the equivalent resistance
Aib5Oqj.jpg

Homework Equations


Req(series) = R1 + R2...
Req(parallel)=(1/R1+1/R2...)^-1

The Attempt at a Solution


I'm having problems understanding how to simplify this circuit.
There should be parallel and series "loops" to simplify but I'm having trouble seeing them.
 
Last edited:

Answers and Replies

  • #2
501
65
I'm having problems understanding how to simplify this circuit.
There should be parallel and series "loops" to simplify but I'm having trouble seeing them.
Mark the junctions where potential is a . Consider a random voltage V , which is the potential in between the 2Ω and 3Ω resistors .

Now draw a fresh diagram , now marking a , b and V , and connecting resistors between the three appropriately . This should help in simplifying the circuit , making it easy to see the series and parallel connections .

Hope this helps .
 
  • #3
5
0
Updated the image with the resistors numerated in red.

Do you have to consider potential?
 
  • #4
501
65
Yes , the potential is what I mentioned in my previous post .
 
  • #5
5
0
What i know is that potential stays the same across parallel sections and is summed up in series.

How does that help me if i cant distinguish which one is in parallel or in series?

Would you mind to explain a little further please, I'm kind of new to this.
 
  • #6
CWatters
Science Advisor
Homework Helper
Gold Member
10,528
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Look at the bottom end of R2...imagine sliding it to the left and around the corner.
 

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