# Circuit (equivalent resistance)

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1. Aug 17, 2015

### triforce

1. The problem statement, all variables and given/known data
Find the equivalent resistance

2. Relevant equations
Req(series) = R1 + R2...
Req(parallel)=(1/R1+1/R2...)^-1
3. The attempt at a solution
I'm having problems understanding how to simplify this circuit.
There should be parallel and series "loops" to simplify but I'm having trouble seeing them.

Last edited: Aug 17, 2015
2. Aug 17, 2015

### Qwertywerty

Mark the junctions where potential is a . Consider a random voltage V , which is the potential in between the 2Ω and 3Ω resistors .

Now draw a fresh diagram , now marking a , b and V , and connecting resistors between the three appropriately . This should help in simplifying the circuit , making it easy to see the series and parallel connections .

Hope this helps .

3. Aug 17, 2015

### triforce

Updated the image with the resistors numerated in red.

Do you have to consider potential?

4. Aug 17, 2015

### Qwertywerty

Yes , the potential is what I mentioned in my previous post .

5. Aug 17, 2015

### triforce

What i know is that potential stays the same across parallel sections and is summed up in series.

How does that help me if i cant distinguish which one is in parallel or in series?

Would you mind to explain a little further please, I'm kind of new to this.

6. Aug 17, 2015

### CWatters

Look at the bottom end of R2...imagine sliding it to the left and around the corner.