Find the Norton equivalent resistance

messier992 · Feb 14, 2019

Homework Statement

Circuit schematic with a 9 V source on the left, resistors of 20 Ω, 5 Ω, 25 Ω, 10 Ω and 60 Ω, and a 1.8 A current source, with terminals a and b on the right.

Homework Equations

Sum of resistance in a parallel circuit: 1/Rt = 1/R1 + 1/R2...
Sum of resistance a series circuit: Rt= R1+R2...

The Attempt at a Solution

Don't know where to go from here:

Handwritten circuit diagram of a network with resistors 20 ohm, 5 ohm, 25 ohm, 10 ohm and 20 ohm, a 1.8 A current source, terminals a and b, followed by an equals sign and a simplified circuit with a dependent voltage source aV, 5 ohm, 25 ohm, 1.8 A source, 20 ohm, and 60 + 10 = 70 ohm.

messier992 · Feb 14, 2019

Actually, I believe this might be the solution. Is this correct?

Handwritten resistor network simplification: a 5 ohm and 20 ohm resistor in series become 25 ohm, which is combined with a 70 ohm resistor and a 25 ohm resistor, followed by a boxed result of 14.79.

Tom.G · Feb 14, 2019

Well I see you got a start and eliminated the Voltage and Current sources. However I can't tell if those sources were replaced by Shorts or Opens. Can you clarify with a better schematic?

Find the Norton equivalent resistance

Homework Statement

Homework Equations

The Attempt at a Solution

Discussion

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