Expressing height in Inverse GeV

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SUMMARY

The discussion centers on converting height into inverse GeV using the principles of quantum mechanics. The user, who is approximately 1.8 meters tall, references the equation for wavelength, λ = h/mc, and notes that both Planck's constant (h) and the speed of light (c) are set to 1 in natural units. By applying the equation E = hν = hc/λ, the user concludes that λ can be expressed as 1/E, which translates to units of 1/GeV when energy (E) is measured in GeV.

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  • Understanding of natural units in physics, specifically h = c = 1.
  • Familiarity with the relationship between energy, wavelength, and frequency in quantum mechanics.
  • Basic knowledge of unit conversion in physics.
  • Concept of inverse energy units, particularly in GeV.
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  • Study the derivation and applications of the energy-wavelength relationship in quantum mechanics.
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  • Learn about the significance of inverse GeV in high-energy physics contexts.
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Students of physics, particularly those studying quantum mechanics and particle physics, as well as educators looking to explain unit conversions in high-energy contexts.

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My physics professor has asked that I express my height in GeV-1. I am about 1.8 meters tall. He has also given me a wavelength equation which goes as follows. wavelength=h/mc. He has also noted that h=c=1. Does anyone have a clue about how to go about converting these units?
 
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Well, at the moment all I can think of is E = h[itex]\nu[/itex] = hc/[itex]\lambda[/itex] which means [itex]\lambda[/itex] = hc/E, and if h = c = 1, then [itex]\lambda[/itex] = 1/E which would have units of 1/GeV if one puts E in GeV.
 

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